How do you Make 0.1M. and 0.001M Sodium Thiosulphate

Dissolve 25 gm of sodium thiosulphate and 200 mg of sodium carbonate in carbon dioxide-free water to produce 1000 ml. Standardize the solution in the following manner                                 

STANDARDISATION (TRIPLICATE)

Weigh accurately about 0.2 gm. of potassium bromate and dissolve sufficient water to produce 250 ml.  To 50 ml. of this solution add 2 gm. of Potassium Iodide and 3 ml. of 2M Hydrochloric acid and titrate with 0.1M sodium thiosulphate solution using starch solution added towards the end of the titration, as an indicator until the blue colour is discharged to end-point  

Every 1 ml of 0.1M sodium thiosulphate is equivalent to 0.002784gm of KBrO3

Calculation

                    Wt. of potassium bromate(mg) × 50 x Potency of potassium bromate× 0.1

 Molarity  =   ------------------------------------

                      Volume consumed (ml) x 2.784 x 250 × 100

SODIUM THIOSULPHATE (0.001M)

PREPARATION

Take 10 ml 0.1M of sodium thiosulphate in a 1000 ml volumetric flask and produce 1000 ml with carbon dioxide-free water. Standardize the solution in the following manner      

STANDARDISATION (TRIPLICATE)

Weigh accurately about 0.05 gm. of potassium bromate and dissolve sufficient water to produce 500 ml.  To 10 ml. of this solution add 2 gm of Potassium Iodide and 3 ml. of 2M hydrochloric acid and titrate with 0.001M sodium thiosulphate solution using starch solution added towards the end of the titration, as an indicator until the blue colour is discharged to a blue coloured end-point  

Each 1 ml of 0.001M sodium thiosulphate is equivalent to 0.00002784gm of KBrO3.

Calculation

               Wt. of potassium bromate(mg) x 10 x Potency of potassium bromate ×0.001 

 Molarity  =  -----------------------------------                                           

             Volume consumed (ml) x 0.02784 x 500 × 10

BANTI SINGH

Hi I'm Banti Singh, a Chemical Engineer! Welcome all of you to my blog. If you got the information right? Share the information. All of you Thank you

Thanks to visit this site.

Post a Comment (0)
Previous Post Next Post